3.49 \(\int \frac {x^2}{(b x^2)^{3/2}} \, dx\)

Optimal. Leaf size=16 \[ \frac {x \log (x)}{b \sqrt {b x^2}} \]

[Out]

x*ln(x)/b/(b*x^2)^(1/2)

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Rubi [A]  time = 0.00, antiderivative size = 16, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {15, 29} \[ \frac {x \log (x)}{b \sqrt {b x^2}} \]

Antiderivative was successfully verified.

[In]

Int[x^2/(b*x^2)^(3/2),x]

[Out]

(x*Log[x])/(b*Sqrt[b*x^2])

Rule 15

Int[(u_.)*((a_.)*(x_)^(n_))^(m_), x_Symbol] :> Dist[(a^IntPart[m]*(a*x^n)^FracPart[m])/x^(n*FracPart[m]), Int[
u*x^(m*n), x], x] /; FreeQ[{a, m, n}, x] &&  !IntegerQ[m]

Rule 29

Int[(x_)^(-1), x_Symbol] :> Simp[Log[x], x]

Rubi steps

\begin {align*} \int \frac {x^2}{\left (b x^2\right )^{3/2}} \, dx &=\frac {x \int \frac {1}{x} \, dx}{b \sqrt {b x^2}}\\ &=\frac {x \log (x)}{b \sqrt {b x^2}}\\ \end {align*}

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Mathematica [A]  time = 0.00, size = 15, normalized size = 0.94 \[ \frac {x^3 \log (x)}{\left (b x^2\right )^{3/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2/(b*x^2)^(3/2),x]

[Out]

(x^3*Log[x])/(b*x^2)^(3/2)

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fricas [A]  time = 0.77, size = 16, normalized size = 1.00 \[ \frac {\sqrt {b x^{2}} \log \relax (x)}{b^{2} x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^2)^(3/2),x, algorithm="fricas")

[Out]

sqrt(b*x^2)*log(x)/(b^2*x)

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giac [A]  time = 0.17, size = 21, normalized size = 1.31 \[ -\frac {\log \left ({\left | -\sqrt {b} x + \sqrt {b x^{2}} \right |}\right )}{b^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^2)^(3/2),x, algorithm="giac")

[Out]

-log(abs(-sqrt(b)*x + sqrt(b*x^2)))/b^(3/2)

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maple [A]  time = 0.00, size = 14, normalized size = 0.88 \[ \frac {x^{3} \ln \relax (x )}{\left (b \,x^{2}\right )^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(b*x^2)^(3/2)*x^2,x)

[Out]

1/(b*x^2)^(3/2)*x^3*ln(x)

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maxima [A]  time = 1.32, size = 6, normalized size = 0.38 \[ \frac {\log \relax (x)}{b^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2/(b*x^2)^(3/2),x, algorithm="maxima")

[Out]

log(x)/b^(3/2)

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mupad [B]  time = 0.07, size = 37, normalized size = 2.31 \[ -\frac {x-\ln \left (2\,\sqrt {b}\,\sqrt {x^2}+2\,\sqrt {b}\,x\right )\,\sqrt {x^2}}{b^{3/2}\,\sqrt {x^2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2/(b*x^2)^(3/2),x)

[Out]

-(x - log(2*b^(1/2)*(x^2)^(1/2) + 2*b^(1/2)*x)*(x^2)^(1/2))/(b^(3/2)*(x^2)^(1/2))

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {x^{2}}{\left (b x^{2}\right )^{\frac {3}{2}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2/(b*x**2)**(3/2),x)

[Out]

Integral(x**2/(b*x**2)**(3/2), x)

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